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- Timestamp:
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Jan 5, 2011, 9:22:29 AM (15 years ago)
- Author:
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Víctor de Buen Remiro
- Comment:
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v10
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v11
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| 59 | 59 | De esta forma tenemos la fórmula de aproximación |
| 60 | 60 | |
| 61 | | [[LatexEquation( \ln p_{i}\backsimeq \mu_{0}+\ln\left(\frac{1}{N}\underset{j=1}{\overset{N}{\sum}}\tilde{\pi}_{i}\left(z_{i,j}\right)\right)+n\ln r_{i,k} )]] |
| | 61 | [[LatexEquation( \ln p_{i}=\mu_{0}+\nu_{i} )]] |
| | 62 | |
| | 63 | [[LatexEquation( \nu_{i}=\ln\left(\frac{1}{N}\underset{j=1}{\overset{N}{\sum}}\tilde{\pi}_{i}\left(z_{i,j}\right)\right)+n\ln r_{i,k} )]] |
| 62 | 64 | |
| | 65 | Puesto que unaa probabilidad ha de ser menor que 1 su logaritmo es siempre negativo, por lo que tenemos una cota para la constante |
| | 66 | |
| | 67 | [[LatexEquation( \mu_{0}<-\underset{i=S'}{\max}\left\{ \nu_{i}\right\} )]] [[BR]] |
| 63 | 68 | |
| 64 | 69 | == Verosimilitud del parámetro == |
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… |
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| 83 | 88 | Sujeto a |
| 84 | 89 | |
| 85 | | [[LatexEquation( \mu_0\leq-\underset{i=S'}{\max}\left\{ \ln\left(\pi_{i}+\underset{j=1}{\overset{k}{\prod}}\pi_{i,j}\right)+n\ln r_{i,k}\right\} )]] [[BR]] |
| | 90 | [[LatexEquation( \mu_{0}<-\underset{i=S'}{\max}\left\{ \nu_{i}\right\} )]] [[BR]] |
| 86 | 91 | |
| | 92 | Resolviendo este problema obtenemos el valor de [[LatexEquation( \mu_{0} )]] que nos permite completar el resto de cálculos. |
| 87 | 93 | |
| 88 | 94 | == Test de super-población == |